*Memos:
- My post explains a string.
splitlines() can split a string at one or more line boundaries as shown below:
*Memos:
- The 1st argument is
keepends(Optional-Default:False-Type:bool). *IfkeependsisTrue, one or more line boundaries are included otherwise they aren't included. - These below are line boundaries:
\n |
Line Feed |
\r |
Carriage Return |
\r\n |
Carriage Return + Line Feed |
\v or \x0b
|
Line Tabulation |
\f or \x0c
|
Form Feed |
\x1c |
File Separator |
\x1d |
Group Separator |
\x1e |
Record Separator |
\x85 |
Next Line (C1 Control Code) |
\u2028 |
Line Separator |
\u2029 |
Paragraph Separator |
v1 = '1 one\n2 two\r3 three\r\n4 four\v5 five'
v2 = '1 one\x0b2 two\f3 three\x0c4 four'
v3 = '1 one\x1c2 two\x1d3 three\x1e4 four'
v4 = '1 one\x852 two\u20283 three\u20294 four'
print(v1)
# 1 one
# 3 three
# 4 four5 five
print(v1.splitlines())
print(v1.splitlines(keepends=False))
# ['1 one', '2 two', '3 three', '4 four', '5 five']
print(v1.splitlines(keepends=True))
# ['1 one\n', '2 two\r', '3 three\r\n', '4 four\x0b', '5 five']
print(v2)
# 1 one2 two3 three4 four
print(v2.splitlines())
# ['1 one', '2 two', '3 three', '4 four']
print(v2.splitlines(keepends=True))
# ['1 one\x0b', '2 two\x0c', '3 three\x0c', '4 four']
print(v3)
# 1 one2 two3 three4 four
print(v3.splitlines())
# ['1 one', '2 two', '3 three', '4 four']
print(v3.splitlines(keepends=True))
# ['1 one\x1c', '2 two\x1d', '3 three\x1e', '4 four']
print(v4)
# 1 one
2 two
3 three
4 four
print(v4.splitlines())
# ['1 one', '2 two', '3 three', '4 four']
print(v4.splitlines(keepends=True))
# ['1 one\x85', '2 two\u2028', '3 three\u2029', '4 four']
v = '1 one 2 two 3 three 4 four 5 five'
print(v)
# 1 one 2 two 3 three 4 four 5 five
print(v.splitlines())
print(v.splitlines(keepends=True))
# ['1 one 2 two 3 three 4 four 5 five']
v = ''
print(v.splitlines())
# []
partition() can split a string at the 1st occurrence of a separator, searching from the left to the right as shown below:
*Memos:
- The 1st argument is
sep(Required-Type:str): *Memos:- It's the separator of the one or more characters to separate a string.
- An empty string cannot be set.
- Don't use
sep=.
- It returns a tuple of 3 elements.
- If
sepisn't found, a tuple of the string itself and two empty strings in order is returned as 3 elements.
v = "It's very very good"
print(v.partition('er'))
# ("It's v", 'er', 'y very good')
print(v.partition('very'))
# ("It's ", 'very', ' very good')
# ↓
print(v.partition(' '))
# ("It's", ' ', 'very very good')
# ↓↓
print(v.partition(' '))
print(v.partition('ER'))
print(v.partition('VERY'))
print(v.partition('really'))
# ("It's very very good", '', '')
print(v.partition(''))
# ValueError: empty separator
v = ''
print(v.partition('er'))
# ('', '', '')
rpartition() can split a string at the 1st occurrence of a separator, searching from the right to the left as shown below:
*Memos:
- The 1st argument is
sep(Required-Type:str): *Memos:- It's the separator of the one or more characters to separate a string.
- An empty string cannot be set.
- Don't use
sep=.
- It returns a tuple of 3 elements.
- If
sepisn't found, a tuple of two empty strings and the string itself in order is returned as 3 elements.
v = "It's very very good"
print(v.rpartition('er'))
# ("It's very v", 'er', 'y good')
print(v.rpartition('very'))
# ("It's very ", 'very', ' good')
# ↓
print(v.rpartition(' '))
# ("It's very very", ' ', 'good')
# ↓↓
print(v.rpartition(' '))
print(v.rpartition('ER'))
print(v.rpartition('VERY'))
print(v.rpartition('really'))
# ('', '', "It's very very good")
print(v.rpartition(''))
# ValueError: empty separator
v = ''
print(v.rpartition('er'))
# ('', '', '')
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